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18 Sep 2007 22:40:21 IST
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both (a) and (b) are correct.
as velocity in vertical plane will be v. but if it's thrown horizontally , then velocity in vertical plane will be zero and only provided by g.
it cant be d. *ever*
it would be (d) if there was no initial velocity v.
*PLZ RATE*
as velocity in vertical plane will be v. but if it's thrown horizontally , then velocity in vertical plane will be zero and only provided by g.
it cant be d. *ever*
it would be (d) if there was no initial velocity v.
*PLZ RATE*
19 Sep 2007 09:56:17 IST
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d is not the correct option
by simple calculations we can derive that the object thrown vertically upwards and the other vertically downwards hit the ground at the same speed provided their initial velocity is the same
they have their y component ut-1/2gt^2 but projectile has its x component also
by simple calculations we can derive that the object thrown vertically upwards and the other vertically downwards hit the ground at the same speed provided their initial velocity is the same
they have their y component ut-1/2gt^2 but projectile has its x component also
19 Sep 2007 15:23:39 IST
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The answer cant be 'D' . It wud have been d had there been no initial velo.
Let me prove it
For the case when its thrown horizontallly
Considering vertical motion
u = 0
a = g
s = h
final velo = (0 + 2ag) ^ 1/2
For the case when its thrown vertically downwards
u = v
a = g
s = h
final velo = (v^2 + 2ag) ^ 1/2
which is ofcourse grtr than the final velo in previous case
Answer wud be A and B
Let me prove it
For the case when its thrown horizontallly
Considering vertical motion
u = 0
a = g
s = h
final velo = (0 + 2ag) ^ 1/2
For the case when its thrown vertically downwards
u = v
a = g
s = h
final velo = (v^2 + 2ag) ^ 1/2
which is ofcourse grtr than the final velo in previous case
Answer wud be A and B
19 Sep 2007 22:24:33 IST
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Answer is (d) only and deedee has given a perfect answer for it. sanky in horizontal throw you are missing the initial horizontal speed of v which will remain till end. When the body reaches the ground its final velocity will be sqrt(2gh) vertically and v horizontaly so its speed still is sqrt(v^2+2hg)
20 Sep 2007 10:31:36 IST
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in case of vertically upward n downward throws, vel. when it touches ground will be same...........max vel will be in the case when it is thrownhorizontally as it has a component velocity in hori direction also....
option D is completely invalid...............velocity does depend upon direction..............consider a case of oblique downward projection where velocity will be max
option D is completely invalid...............velocity does depend upon direction..............consider a case of oblique downward projection where velocity will be max
















since when thrown horizontally its vertical initial velocity is 0
but in the other cases it is v downwards.
pls check again