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Ankit Bisht's Avatar
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18 Sep 2007 22:00:34 IST
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Conceptual Ques
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A heavy stone is thrown from a cliff of height h with a speed v. The stone will hit the ground with max speed if it it thrown
a) vertically upward
b) vertically downward
c) horizontally
d) the speed does not depend on the initial direction
  plz explai

ans is (d)


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New kid on the Block

Joined: 10 Aug 2007
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18 Sep 2007 22:19:26 IST
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pls recheck the answer coz i think its (b)+(a)
since when thrown horizontally its vertical initial velocity is 0
but in the other cases it is v downwards.

pls check again
Gaurav |spideyunlimited| Ragtah's Avatar

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18 Sep 2007 22:40:21 IST
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both (a) and (b) are correct.
as velocity in vertical plane will be v. but if it's thrown horizontally , then velocity in vertical plane will be zero and only provided by g.

it cant be d. *ever*

it would be (d) if there was no initial velocity v.

*PLZ RATE*

New kid on the Block

Joined: 8 Sep 2007
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18 Sep 2007 23:07:54 IST
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if v consider this ques by work-energy principle rather than kinematics:
change in k.e is made up by dec in pot energy(which depends only on vertical height)
so there is always the same final velocity (irrespective) of manner it is thrown.
ramyani chakrabarty's Avatar

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18 Sep 2007 23:14:50 IST
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Yes,  the speed does not depend on the initial direction.

paris mulye's Avatar

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19 Sep 2007 09:56:17 IST
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d is not the correct option
by simple calculations we can derive that the object thrown vertically upwards and the other vertically downwards hit the ground at the same speed provided their initial velocity is the same
they have their y component ut-1/2gt^2 but projectile has its x component also
aNdRoMeDa's Avatar

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19 Sep 2007 10:19:40 IST
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ya, i 2 feel dat speed, vel. do not depend on d initial direction as
v=u+at
thus, v depends on u ,a& t
v^2=u^2+ 2as
here v depds on u, a,& s(displacement)
displacement is same 4 any case
thus, ans is (d)
sankydreams's Avatar

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19 Sep 2007 15:23:39 IST
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The answer cant be 'D' . It wud have been d had there been no initial velo.
Let me prove it
For the case when its thrown horizontallly
Considering vertical motion
u = 0
a = g
s = h
final velo = (0 + 2ag) ^ 1/2

For the case when its thrown vertically downwards
u = v
a = g
s = h
final velo = (v^2 + 2ag) ^ 1/2
which is ofcourse grtr than the final velo in previous case
Answer wud be A and B
Krishna Gopal Singh's Avatar

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19 Sep 2007 22:24:33 IST
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Answer is (d) only and deedee has given a perfect answer for it. sanky in horizontal throw you are missing the initial horizontal speed of v which will remain till end. When the body reaches the ground its final velocity will be sqrt(2gh) vertically and v horizontaly so its speed still is sqrt(v^2+2hg)
Gaurav |spideyunlimited| Ragtah's Avatar

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19 Sep 2007 22:33:22 IST
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oh yes we forgot that the speed will be the horizontal plus the vertical component.. gud gud
tht was the only confusion. allright den :)
thevyzz's Avatar

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19 Sep 2007 22:44:39 IST
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it can be simply put on conservation of energy principle
Initial energy = mv^2/2 + mgh
final energy = mV^2/2 +0
so all the potential energy will be converted into kinetic energy
so the velocity will be the same

New kid on the Block

Joined: 13 Sep 2007
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20 Sep 2007 10:31:36 IST
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in case of vertically upward n downward throws, vel. when it touches ground will be same...........max vel will be in the case when it is thrownhorizontally as it has a component velocity in hori direction also....
option D is completely invalid...............velocity does depend upon direction..............consider a case of oblique downward projection where velocity will be max
Prantik Chatterjee's Avatar

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20 Sep 2007 11:44:49 IST
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If the body is projected horizontally then obviously the vertical component is 0 and so it will behave as free fall.So the answer will be D when the initial vertical component is 0
yash shah's Avatar

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20 Sep 2007 12:06:38 IST
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ans d as it acts under a constant gravitation field



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