Home » Ask & Discuss » Physics. » Mechanics « Back to Discussion



Mechanics

VARUN  RAJ's Avatar
Blazing goIITian

Joined: 16 Mar 2008
Post: 1825
11 May 2009 12:48:55 IST
0 People liked this
13
492 View Post
CONFUSING SUM
Kinematics , NewtonsLawsCirMotion , Work Power Energy collisions , Rotation , Gravitation , Simple Harmonic Motion , Fluid Mechanics , Materials Wave Sound , Super Position , units dimensions , com momentum , shm , wave sound

A ring of mass m and radius r is lying on a horizontal table . A bullet of mass m moving with vel v strikses the ring tangentially and gets embedded in it . Find the vel of the bullet in the groungd frame just after the impact..SOLVE IT USING   IMPULSE METHOD 


Share this article on:

Comments (13)

Ady JEE-09 AIR 294's Avatar

Hot goIITian

Joined: 6 Nov 2008
Posts: 145
11 May 2009 20:32:33 IST
0 people liked this

let impulse imparted by point mass to the ring be J. Let final velocity of com of ring is v1 and final velocity of point mass is v2. angular velocity of ring be w. Then J = mv1, -J = mv2 - mv , and v2 = v1 + rw, and Jr = Iw

kindly rate if correct...

VARUN  RAJ's Avatar

Blazing goIITian

Joined: 16 Mar 2008
Posts: 1825
12 May 2009 09:01:28 IST
0 people liked this

kkk but abt which pt should i be calculate and why!!!!!!!!this is the question man
VARUN  RAJ's Avatar

Blazing goIITian

Joined: 16 Mar 2008
Posts: 1825
13 May 2009 09:43:49 IST
0 people liked this

ANY MORE TRIES
Ady JEE-09 AIR 294's Avatar

Hot goIITian

Joined: 6 Nov 2008
Posts: 145
13 May 2009 09:58:49 IST
0 people liked this

conserve angular momentum about com of system. First linear momentum mv = 2mv1 or v1 = v/2. Then mvr/2 = I(net about com of system)w. Hence velocity of point mass is v1 + r/2 w

I(net) = mr^2 + 2*m(r/2)^2

rates if correct...

Akshay's Avatar

Blazing goIITian

Joined: 27 Dec 2007
Posts: 689
13 May 2009 10:27:57 IST
2 people liked this

any free system has a tendency to rotate about its COM

COM of the system= midpoint of the radius joining the centre of the ring to the attached mass

now, linear impulse= J change in linear momentum

J=m(vc-v )=-mv/2
vc=v/2 by conservation of linear momentum,

angular impulse= change in angular momentum about COM

J=-mvr/4=Iw-mvr/2

mr2w/4=mvr/4

w=v/r

therefore, net velocity= v/2 +(r/2)w= v???

 

 

VARUN  RAJ's Avatar

Blazing goIITian

Joined: 16 Mar 2008
Posts: 1825
13 May 2009 22:01:42 IST
0 people liked this

I ACCEPT UR ANSWERS I MYSELF SOLVED IT BY THIS METHOD BUT I WANT TO KNOW WHY NEW COM
Ady JEE-09 AIR 294's Avatar

Hot goIITian

Joined: 6 Nov 2008
Posts: 145
14 May 2009 07:55:24 IST
1 people liked this

NO, you can conserve angular momentum about any point. See, before collision com of system is moving in straight line. By conservation of linear momentum com will continue along that line. As there is rotational motion after the collision this rotation will obviously take place about com of  system as it moves along line. As rotation is about com of system conserving angular momentum about com becomes easier. When you conserve angular momentum about say, an axis placed initially at the centre of ring, then the final angular momentum will be written as L = Lc + mr/2v. Remember that the system is rotating about com of system C.  About a stationary axis initially placed at ring centre the motion of the system is rotation + translation.  the ring +particle system rotates about C. And therefore, the angular momentum of the system about a stationary axis initially placed at the centre of ring will be Lc + mr/2v. Where Lc is angular  momentum of system about C( Ic is MI of system about C). and v is velocity of C

L = Lc + m r /2X v

IF YOU CONSERVE ANGULAR MOMENTUM ABOUT C ITSELF THEN YOU DONT HAVE TO WORRY ABOUT MRV PART.

rates please..

if not understood nudge me

Ady JEE-09 AIR 294's Avatar

Hot goIITian

Joined: 6 Nov 2008
Posts: 145
14 May 2009 08:00:05 IST
1 people liked this

 The system rotates about com of the system hence if u r finding L wrt axis initially placed at the center of ring then it will be given by Lc + mr/2v

Please rate me

Sujit's Avatar

Blazing goIITian

Joined: 11 Mar 2009
Posts: 1345
14 May 2009 08:21:19 IST
1 people liked this

 conservation of angular mom abt the center

conservation of linear mom

V1=V/2

therefore velocity pf bullet=        =               V

VARUN  RAJ's Avatar

Blazing goIITian

Joined: 16 Mar 2008
Posts: 1825
14 May 2009 10:52:13 IST
0 people liked this

actually all ur answers r wrong the rite answers come by conserving angular momentum u get a different answers
VARUN  RAJ's Avatar

Blazing goIITian

Joined: 16 Mar 2008
Posts: 1825
14 May 2009 11:01:40 IST
0 people liked this

sorry dudes   i got my mistake      was assuming that the system rotated abt the combined com     .... but it shuld rotate abt  the centre of the ring   anyways thanx fir the troubles


 

Sujit's Avatar

Blazing goIITian

Joined: 11 Mar 2009
Posts: 1345
14 May 2009 11:04:20 IST
0 people liked this

jst rate all of us then fr our hard wrk
Ady JEE-09 AIR 294's Avatar

Hot goIITian

Joined: 6 Nov 2008
Posts: 145
15 May 2009 08:57:39 IST
0 people liked this

 mvr/2 = (mr^2 + m(r/2)^2 + m(r/2)^2) w

mvr/2 = 3/2 mr^2 w

v = 3rw or w = v / 3r

hence velocity of particle after collision = v/2 + r/2 * v/3r = 2v/3

rates please




Quick Reply


Reply

Some HTML allowed.
Keep your comments above the belt or risk having them deleted.
Signup for a avatar to have your pictures show up by your comment
If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Find Posts by Topics

Physics.

Topics

Mathematics.

Chemistry.

Biology

Parents

Board

Fun Zone

Sponsored Ads