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Joined:	25 Feb 2008
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29 Mar 2008 19:01:59 IST

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308

could you please show me how you get to the answer??

None

4. Load B is connected to a double pulley by one of the two inextensible cables (figure A). The motion of the pulley is controlled by the cable C, which has a constant acceleration of 0.225 m/s² and an initial velocity of 0.3 m/s both directed to the right. What is the number of revolutions executed by the pulley in 2 s ?

(a)
(b)
(c)
(d)
Ans4 (d)

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Akhil

Blazing goIITian

Joined: 17 Jan 2008

Posts: 1451

29 Mar 2008 19:08:08 IST

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initial angular velocity of inner pulley
w=v/r
=0.3/0.075
=4 rad/sec
now the angular velocity of pulley system is same for both wheels

also

=a/r
=0.225/0.075= 3 rad/sec²
use std equation

=wt+1/2

t²
=4(2)+1/2(3)(2*2)
=8+6=14 radians
now revolutions=

/2 pi
-=14/2 pi
=7/pi

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