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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 16:29:58 IST
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hi guys,plz help me out with this one!!! is there any way to memorise the results of cross-product of unit vectors.e.g. tell how to know what is i cross j,j cross i, -j cross -i,-k cross -i and similarly other cross products.dot product is too easy.plz do help me out with this one.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 16:33:59 IST
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See,consider a circle in which the elements i,j and k are arranged.Now,go anti clockwise.
i --- k \ / j i x j will be k.j x k will be i.kxi will be j.Suppose you have i x k.Then here it will be clockwise and hence a -ve sign will come.i.e,i x k= -j.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 16:41:16 IST
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did you get it??
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Please watch the BPL match between ManUtd and Arsenal on Sunday at 5:55pm and support only ManUtd...for BPL lovers,update:ManUtd-2 Arsenal-1...
Viva Ronaldoooo
Viva Ronaldoooo
Viva Ronaldoooo
Running down the wing,
Hear United sing,
Viva Ronaldoooo.
-United supporters new chant!!!
Team Plyd Pts
United 32 76
Cls 32 71
Arse 32 70
Who are Liverpool????? |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 16:45:37 IST
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see in xyz x cums 1st similarly i cums 1st in ijk so we memorize dem
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2008 16:46:11 IST
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use series i j k in direction of k i.e ixj =k jxk =i if the series is in opposite direction apply negative signs jxi =-k
hope u got it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 21:32:50 IST
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thnxs guys what about j cross i?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 21:35:27 IST
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Hey, you are going anticlockwise so same iXj with a negati sig .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 21:55:27 IST
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if you write i,j & k in traingle shape like i k j and moves to clockwise direction you will get i * j = k , j * k = i,k * i =j now if you moves anticlokwise direction i * k = -j , k * j = -i , j * i = -k
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 23:04:53 IST
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i totally agreed with rathin
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 23:22:12 IST
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imagine i along x axis j along y axis k along z axis
if u want to find i X j = then curl your right handfingers from x axis to y , this will give u k similarly i X k = - y axis = -j
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 23:28:07 IST
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hey kane........see........
when u move in this manner.......
from i to j to k to i....take it as positive.....if order is opposite take it as negative.....
now remember just one more thing....cross product of any two unit vectors gives the third one.......
for example.........
i x j = k but j x i = -k j x k = i but k x j = -i k x i = j but i x k = -j
hope this helps u..........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2008 23:48:52 IST
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ya..... tats ryt.......... neways.......... the exact1 is..........
Since sin 0 = 0 and sin 90 = 1 and each vector is of unit length, we have i x i = j x j = k x k = O, (the zero vector). Also, i x j = k and j x k = i and k x i = j while j x i = - k and k x j = - i and i x k = - j. You can see how the various plus and minus signs come by using the right-hand rule for each product. I've shown this for the case i x j = k :
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 12:56:35 IST
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thnxs a lot everybody for replying!!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Apr 2008 23:23:11 IST
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Hey just see the attached image below. If u take i x j then u get k( see the cyclic motion) similarly, j x k = i and, k x i = j.
If u want something in the direction opposite to that of the given direction then the result will have a negative(-) sign.
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