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Mechanics

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16 Sep 2007 19:21:06 IST

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664

d.c. pandey ques

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a point mass starts moving along x axiswith constant acceleration.the displacement measured from a convenient position,is 2m at time t=0 and is zero at time t=10 s.if the velocity of the particle is momentary zero when t=6s,determine the acceleration a and the velocity v when t=10s

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Amrita bhavaraju

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16 Sep 2007 19:31:07 IST

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whats the ans.????????

'',' Off to a nu start!!

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16 Sep 2007 19:33:53 IST

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u = 0 , t = 10 , s = 2

2 = a . 100 / 2

a = 0.1 m/s2

v = 0 + 0.1 . 10 = 1m/s

Amrita bhavaraju

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17 Sep 2007 14:43:32 IST

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hey shubham.....my ans. is this..plzzz check this out and correct me if m wrong anywhere.....

the body is moving along x-axis and after some time the displ. is zero so the point of view is also on x-axis....the body is moving witrh accl. and velocity is zero at t=6 therefore it is moving with retardation but it reaches the point of view at t=10 so the point of view is behind the initial point of the body.. so

0=6a+u...........................................................where u is the initial velocity and a is the retardation.

==> a= -u/6

but 10u + 50a=2

==> -60a+50a=2

==> -10a=2 ==> a= -0.2m/s2 therefore u=1.2......velocity at t=10 = u + at = 1.2-10(0.2)=1.2-= = -0.8 = 0.8m/s towards the point of view..

if u find it useful plzzz rate.. :)

Love Shah

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17 Sep 2007 18:57:08 IST

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akanksha srivastava

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17 Sep 2007 19:35:16 IST

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u r correct amrita

Amrita bhavaraju

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19 Sep 2007 18:59:24 IST

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thanxx

Amrita bhavaraju

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20 Sep 2007 19:24:33 IST

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its because the displacement=2....from initial point to the point of view....

Amrita bhavaraju

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20 Sep 2007 19:28:45 IST

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and this happens after 10 sec ....

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