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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 14:46:14 IST
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A stick of length L is thrown up from your hand such that at the time of throwing the velocity of the end form which stick was being thrown was zero. The stick returns to the hand (at the same level) after making N turns in air. Find the max height to which the stick wil go during its flight.
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17 Feb 2007 17:07:29 IST
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0.5 NL:is the answer
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will make it BIG! |
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18 Feb 2007 14:59:17 IST
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your answer is incorrect correct ans is  NL/4 give your solution also
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18 Feb 2007 15:05:08 IST
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in 2T time it rotates N times therefore frequency=2T/N=2 /  . =V/L.V=(2gh)^0.5 |
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18 Feb 2007 15:07:51 IST
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you are using missing some concept in the question
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18 Feb 2007 15:09:53 IST
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what is wrong im using
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18 Feb 2007 15:12:11 IST
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which of my concept is wrong
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18 Feb 2007 15:13:30 IST
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think hard my friend. better understand the question more deeply.
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18 Feb 2007 15:16:22 IST
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angular velocity of rod will not be at the end but at the centre of mass of stick
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18 Feb 2007 15:16:41 IST
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if ur so sure about my concept being wrong then tell me if u know the method then let me know!
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18 Feb 2007 15:17:07 IST
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now try to correct your solution
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18 Feb 2007 15:18:13 IST
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is it omega = 2V/L ur saying
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18 Feb 2007 15:21:37 IST
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thist was the trick in the question that where about to consider the angular velocity of stick V= WL/2 ; W is the angular velocity now follow your own solution
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18 Feb 2007 15:22:03 IST
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ya it is omega=2V/L and answer comes out to be as ur saying
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18 Feb 2007 15:22:22 IST
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yes now you have got that to correct
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