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Mechanics

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23 Nov 2008 13:03:24 IST

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displacement is given by s=6+12t-2t2 (thts 2t square) ...then the distance in 5 sec is

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displacement is given by s=6+12t-2t2 (thts 2t square) ...then the distance in 5 seconds is......

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((Sumanta)) Rocker is BACK with a BANG!!

Scorching goIITian

Joined: 18 Aug 2008

Posts: 248

23 Nov 2008 14:04:52 IST

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well.......... by the equation given ... u can only find out the displacement in 5 sec.......
What to be done for the DISTANCE??.........

Its some data might be missing......

akki ~~ unlucky forever ~~

Blazing goIITian

Joined: 11 May 2008

Posts: 491

23 Nov 2008 14:07:34 IST

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my ans is comming 32 m.....................

waterdemon

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Joined: 11 Jun 2007

Posts: 1048

23 Nov 2008 16:05:32 IST

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Very easy sum.Distance covered is to be found out.Therefore.

Let displacement at t = i sec be given by S_i .

Therefore,

S₀ = 6m

S₁ = 16m

S₂ = 22m

S₃ = 24m

S₄ = 22m

S₅ = 16m.

Thus the distance covered can be given by

= (S₁-S₀) + (S₂-S₁) + (S₃-S₂) + (S₄-S₃) + (S₅-S₄)

= 10 + 6 +2 + 2 + 6

= 26m.

Hence the distance travelled must be = 26m.

And if you want the displacement then it is S = 16m.

you can say X = 10m from starting position.

Hope it helps ya.

Cheers !!!!!!!!!!@@@@!!!!!!!!!!!! :)

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