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30 May 2012 15:58:52 IST

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for the ans you gave me i would like to have a clarification.after the projectile reaching maximum height it behaves as freely falling in vertical motion.so for t>time of ascent, its vertical displacement from ground will be max height-1/2g(t-time of ascent)^2

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dirichet

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Joined: 22 May 2012

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30 May 2012 17:31:29 IST

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which question are you refering to

Tanveesh Inani

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Joined: 29 May 2012

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1 Jun 2012 12:33:24 IST

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which question are you asking of??

Aman Raghuvanshi

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Joined: 13 Nov 2011

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1 Jun 2012 19:20:21 IST

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what world are you in?

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