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14 Feb 2012 14:41:59 IST

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elementary mechanics

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an airplane has a speed of 600km/h with respect to air . it has to fly a distance of 800kmnorthward . in what direction should it fly if a steady wind blowing at the speed of 120km/h from west?what will its speed with respect to the ground be ? draw the relevant diagram for the calculations

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Shvm Gyl

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14 Feb 2012 16:12:10 IST

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http://www.google.co.in/imgres?q=north+east+west+south&start=18&num=10&hl=en&gbv=2&biw=1024&bih=653&tbm=isch&tbnid=EUQqMvxPdiWwHM:&imgrefurl=http://ugconlinecoaching.blogspot.com/2009/11/analytical-reasoning.html&docid=vRUCjkqWJZ3RkM&imgurl=http://i46.tinypic.com/fdardu.jpg&w=448&h=336&ei=ETg6T_3yFMTirAeikPXKCA&zoom=1

the wind is blowing towards east (v_w = 120km/h),so show v_w vector towards E and the plane has to go towards north (v_p = 600km/h) then, it must head towards north-west direction with v_psuch that v_p/w is towards north. So accordingly put the vectors acc to directions and then U will be able to get to the answer of your question.

Try Hard Dont Give Up :)

abs

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14 Feb 2012 16:44:40 IST

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the plane should fly in the northwest direction

from the right angled diagram ,,,,,,600km/h is a resultant of velocity 120km/h

600^2=120^2+v^2

v^2=345600

v=587.90km/h

and direction resultant is given by

sin(theta)=120/600

theta=sin(120/600)

theta=11.54 (degrees)

speed wrt to ground=600cos(theta) = 600cos(11.54)=600*0.51=306km/h

hope its the way it should be

correct me if im wrong

Shvm Gyl

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Joined: 14 Feb 2012

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23 Feb 2012 08:06:27 IST

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hey brother

still wrong

we do not know the resultant velocity towards north

v^2 = 600^2 + 120^2 + 2(600)(120)cos(theta)

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