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5 May 2007 16:58:33 IST

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FLUID MECHANICS

Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Mechanics

THE PRESSURE IN A LIQUID AT TWO POINTS IN THE SAME HORIZONTAL PLANE ARE EQUAL .CONSIDER AN ELAVATOR ACCELERATING UPWARD AND A CAR ACCELERATING ON A HORIZONTAL ROAD. THE ABOVE STATEMENT IS CORRECT IN a)THE CAR ONLY b)THE ELAVATOR oNLY c)both of them

Comments (5)

Manasi

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5 May 2007 17:03:10 IST

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m nt that gud in physics, but still this is what i think...

it should be the same in elevator, as the buoyant force will only work in vertical direction , and that too equally...

while when the car is accelerating horizontal plane, then thr will be acceleration in two directions, g in downward and a along horizontal axis, (see HCV, its given thr), so thr will be pressure difference...

nitin tewari

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5 May 2007 17:07:15 IST

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ans=elevator only.

soln: when the system is in car a pseudo force is acted upon the fluid particles against the motion i.e backwards so a slanted surface is obtained (and all points on a line parallel to the surface formed will hve same pressure (isobaric))

but in elevator each particle on same horizontal level is acted by same force so net pressure diff bet them is zero(i.e in this case isobaric points lie along horizontal lines)

raja tomar

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5 May 2007 17:45:21 IST

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well this holds true for both the cases.

edison

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6 May 2007 13:46:46 IST

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I agree with Nitin's argument.

nikhil handa

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6 May 2007 19:46:14 IST

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well NITIN has explained it well,but to do it quickly what u can think is that when there is a horizontal acc.(as in case of car)then it tends to form an angle
$=tan inverse a\g where a is the acc. of car,quite logically if it forms an angle the point on the left will be diplaced by distance
x tan$,
where x is the distance between the two points.

rate me plssssssss

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