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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:17:54 IST
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plz help me...the question is to find the velocity of the water at point B .....in the solution they say that pressure at P =pressure at B....velocity at P is same as velocity at B but there is a potential energy difference between P and B!!!!!! where does the energy go!!! and another doubt is....if water is considered incompressible....then in a steady streamline....is it that the magnitude of velocity at all points must be same ????? if so how come when u apply bernoullis theorem to water flowing in a tube....and if p1+rowgh1 is not equal to p2+rowgh2....then we get that v1 not equal to v2....but the liquid is incompressible and this is not the case!!!! what is the flaw!!!!??????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:24:08 IST
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oyy wers B here?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:24:52 IST
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its given right....at the bottom of the siphon...anyway sorry for the bad diagram...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:24:59 IST
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ok sorry my frnd i found it out
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:26:09 IST
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i think we can apply Bernoiulli equn only 4 incompresseble liquids...so if the ques is about compressible liq...then it involves higher mathematics.......__
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:30:36 IST
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no question is about incompressible liquids only....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:31:54 IST
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see yaar 2 do a work v need energy n any machine on earth is not 100% efficient 2 raise d water upwards v require some energy if u wait 4 few more minutes i wud try 2 calculate d energy
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:33:41 IST
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if its about incompressable liiq, then apply bernoulli equ at A and at B and get the vel by applying the equ of continuty ..???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:39:27 IST
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aree yaar see here in a stream line flow d velocity of a iven particle is not same at all points its actually : if v consider a point P den d velocity of a given liquid at P is constant n 1 more my frnd see by bernoulli principle
P1 +pgh1 +1/m1v1^2 = P2 +pgh1 + 1/2 m2v^2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:41:37 IST
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thts right as ayshwarya posted we've got toapply Bernoulii theroem...and equ of continuty
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:42:06 IST
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yes u are right thanks....but then i must say that the solution given is wrong right???? i mean...they say that vp=vb but this is not possible.....ok thanks.... that means that incompressible liquid doesnt mean speed at ALL points is constant....but in the solution they are taking like that...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:46:30 IST
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Actually,they maybe right to some extent... see,P and A are at the same horizontal level and we know that pressure at pts. at same horizontal level is same since pressure at A is atm. pressure,pressure at P is also atm. pressure pressure at B is also atm. pressure as seen in the diag...thus pressure at P=pressure at B..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:50:12 IST
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well mainly im not concerned about the pressure...im concerned about the "same velocity" thing.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:55:06 IST
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Are A and P along the same line???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Mar 2008 23:57:33 IST
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