IIT JEE , AIEEE Forum - Physics , Mechanics

zeeshanp

acc to Bernoulli's theorem

p/

+1/2mv² + gh= constant...................

but for horizontal flow h is constant.............and then how does the equation become p/row +1/2mv²= constant??????

and further more how does this equation show that if velocity of the fluid increases then pressure decreases and vice versa

anant_c

here...the fluid flows only when a force is put onto it na...

zeeshanp

i never understud any thing dude..........................

zeeshanp

all answers will be rated.................

anant_c

ok....take h to be zero(for reference pt)...now p+Dmv^2/2=constant....==> p=constant-Dmv^2/2

or if v changes p changes....now if v has to change then p will change as the fluid will accelerate...

and pressure in an accelerating fluid is given by dp/dx=(D)a

a=acceleration
here D =density

antonyajay21

here is u'r ultimate answer.

P1/row1+1/2M1V1^2+gh=P2/row2+1/2M2V2^2+gh

here 'gh' gets cancelled on both the sides.Therefore at const height the eqn. the eqn. is P/row+KE=const.

antonyajay21

rate me if u like

learner

Once you get P/d + 1/2mv^2=constt.(d=density) ,

P=[constt.-1/2mv^2]d

Naturally if P increases,v will decrease to maintain equality.

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