IIT JEE , AIEEE Forum - Physics , Mechanics

anant_c

A container is filled with water,accelerating along the positive x axis on a smooth horizontal surface.The velocity of efflux of water at a point at point P at the bottom of the tank near its left most corner is?
a)4.43m/s
b)5.48m/s
c)4m/s
d)3m/s
Now,my question is...isnt this question incomplete...the water's free surface will make an angle of 45 degrees...so we need more dimensions...

anant_c

?????

spideyunlimited

Velocity of efflux only depends on downward pressure at the bottom point..
Due to horizontal acceleration there is no effect of it.

so answer is
v = root(2gh)
= root(2*9.81*1)
= 4.43 m/s

(a)

anant_c

sry..Thats...wrong....anyway...

this is as the surface is going to be slanted...

so...if u derive the expression using work...u get a different ans...

elastiboysai

i think d ans is 5.48 m/s
obv veloc of efflux shd b >^{[ ]}

2gh .
so this is the only poss. option??

anant_c

thts corct.....but i got the ans assuming it to b a
square container..

also...actually
applying the bernoulli eqn here is incorrect ,,,isnt it?as this isnt streamlined flow....if u derive the expression u get sumthn different

Ask & Discuss Questions with Community & Experts