IIT JEE , AIEEE Forum - Physics , Mechanics

deep01

2 tuning forks A and B produce 4 beats/sec. .On loading B with wax, 6 beats r heard.If the quantity of the wax is reduced the number of beats per seconds again comes to 4.Find the frequency of B,if frequency of A is 256hz??

PLEASE TELL ME WHAT DO IN SUCH TYPE OF QUESTION.

truly

freq of A = 256 hz,,,,,,,, freq of B= B hz

in normal mode 4 beats....
thus

256 - B = 4 ===> B = 252 Hz
OR
B - 256 = 4 =======> B = 260 Hz

Now whn B is loaded with wax its frequency decreases and it produces 6 beats with A...if B is 252 Hz thn chngd frequency shud b 250 hz to produce 6 beats with A, and whn little wax is loaded it produces 4 beats in tht case its freq shud b 252 hz but tht is not possible coz B's natural frequncy is 252 and whn if also little wax is loaded frequency shud decrease...so it is out of question of B being 252 Hz.....

Now whn B is 260,,,it is loaded with wax its freq decreases to 250 hz to produce beats ,,,and whn loaded with little wax its freq is 252 hz to produce 4 beats....

So ans is 260 Hz....

I think this explanation cud clear ur concept

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