IIT JEE , AIEEE Forum - Physics , Mechanics

umang

Two objects A and B are thrown upward simultaneously with the same speed . The mass of A is greater than B . Suppose air resistance is equal on both bodies .

(a) The two bodies will reach the same height

(b) A will go higher

(c) B will go higher

mayur1412

A will go higher than B bcoz momentum is decided by two factors
1. mass
2.velocity
as da velocity of projection is same..so momentum is decided by mass..
higher da mass higher will be da height
hence A has greater mass...hence greater height..!

anirudh1990

i think it is Athat goes higher as it would greater energy than B at the same height.

please confirm the answer.

sen_holmes

i think the ans ia a)

bcoz .........

let mass of a=m1

let mass of b=m2

now initial vel of both=u

final vel of both=0

change in k.e =change in p.e

therefore

for a

1/2*m1*(-u^2)=-m1*g*h1 h1=dist travelled by a

u^2/2=gh

h=u^2/2g

for b

1/2*m2*(-u^2)=m2*g*h2 h2=dist travelled by b

simplifying

h2=u^2/2g

therefore h1=h2

nunoxic

(A)

phalgun_g

I think its (a) or(b)

It is (a) because.....

that is due to the perspective of energy and gravitational force.....

if a body is thrown upwards as in this case....its kinetic energy is max initially and keeps on decreasing with height....

so initially KE of A is higher than B cos it has a greater mass.....

so ke of b decreases and becomes zero earlier than that of A ......

so A moves higher than B ...... only if gravitational force exerted by earth is neglected ....

If gravitational force exerted by earth is considered then

answer is (b)

because gravitational force is directly proportional to mass of the body.....

since mass of A is greater than that of B ......

greater downward force is acting on it than that on B ......

so in this case both reach the same height.....

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