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Mechanics
15 Mar 2008 19:39:32 IST
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a geostationary satellite is orbiting in an polar orbit
the stationary performs revolution around the earth and also performs the self rotational motion in such a way that the axis of rotation makes an acute angle of 60
degree with polar orbit
find the equation with usual notation of centripetal force experienced by a astronaut
inside the satellite if the frequency of rotation is 60 times more the frequency of revolution.
Comments (12)
shridhar ramachandran
Scorching goIITian
Joined: 30 Jan 2008
Posts: 203
16 Mar 2008 01:39:22 IST
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your first line itself is wrong mate.. geostationary satellites revolve ONLY around the equator 
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16 Mar 2008 19:23:10 IST
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as Hash include has stated it is impossible for a geostationary satellite to be placed anywhere other than directly above the equator then only both will have the same time period and angular velocity other wise the path of the satellite being circular and that of earth decreasing in radius as we approach the poles causes time lag
as for additional info
hash include is an ace in the field of physics my best friend.he has never made a mistake what material have you referred???
4 Apr 2008 20:46:42 IST
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See the satalite is revolving in equitorial plane so it can be geostationary. Its sense of rotation has no effect on the fact whether it is geostationary or not.
As far as centripetal force, that will depend on the distance of astronaut from the satalites axis as well as the distance of satelite from the earth.
The acceleration of astronaut will be vector sum of r*omega1^2 + R*omega2^2 where omega2 is 2*pi/24 hrs and omega1=60*omega2.
Now as the direction of these acceleration are varying hence it will be difficult to resolve them. Moreover i am not sure how will you define centripetal force. Is it force along satelite axis or force along the earth.
As far as centripetal force, that will depend on the distance of astronaut from the satalites axis as well as the distance of satelite from the earth.
The acceleration of astronaut will be vector sum of r*omega1^2 + R*omega2^2 where omega2 is 2*pi/24 hrs and omega1=60*omega2.
Now as the direction of these acceleration are varying hence it will be difficult to resolve them. Moreover i am not sure how will you define centripetal force. Is it force along satelite axis or force along the earth.
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