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Mechanics

Cool goIITian

 Joined: 15 Oct 2011 Post: 32
11 Apr 2012 21:17:21 IST
3 People liked this
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friction
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what is d accleration of a block of which is moving up the incline of inclination theta  and coefficient of friction "mu"??

New kid on the Block

Joined: 30 Jul 2011
Posts: 8
12 Apr 2012 01:19:54 IST
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It is moving up by certain inclination force F so acceleration is F-Mgsin"theta"-uMgcostheta"=Ma

Hot goIITian

Joined: 11 Mar 2012
Posts: 124
12 Apr 2012 11:00:59 IST
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It is moving up by certain inclination force F so acceleration is F-Mg sin-u Mg cos  =Ma

Forum Expert
Joined: 23 Jan 2007
Posts: 7958
12 Apr 2012 23:26:22 IST
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$F=mgsin\theta -\mu mgcos\theta$

$\Rightarrow ma=mgsin\theta -\mu mgcos\theta$

$\Rightarrow a=gsin\theta -\mu gcos\theta$

Cool goIITian

Joined: 15 Oct 2011
Posts: 32
13 Apr 2012 06:54:12 IST
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Sir,

i think that is the accln of the block while it is moving down the incline  ??

New kid on the Block

Joined: 7 May 2009
Posts: 1
13 Apr 2012 14:16:33 IST
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yes third reply is for acceleration down the rough incline plane , First and second reply are correct .   visit samrinsharmadotcom for Free online AIEEE objective test series ..   :)

New kid on the Block

Joined: 13 Apr 2012
Posts: 4
13 Apr 2012 20:14:20 IST
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No i think none of you are correct one... The sure answer for above question is a=-g(sin@+mucos@) where @ implies theta and mu implies coefficient of kinetic friction... hoe you all are satisfied by this answer.. please comment it if any wrong...

Cool goIITian

Joined: 21 Mar 2012
Posts: 37
15 Apr 2012 17:23:45 IST
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a= gsin theta+mu g cos theta

New kid on the Block

Joined: 15 Apr 2012
Posts: 18
15 Apr 2012 17:26:54 IST
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chuutttiya sawaal hai.........harammmm khoor the question is incomplete

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