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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 12:37:48 IST
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two blocks of masses m a=2kg and m b=4kg are kept on an inclined plane of inclination  = 37degree as shown.The coefficient of friction bw A and B is 1 and bw B and surface is 2. accelerations of blocks A and B are a 1 and a 2. then match the following. column I column II 1.a 1=a 2 A. 1= 0.3 and 2 = 0 2.a 1 a 2 B 1= 0.8 and 2 = 0.8 3.if work done by friction on block B is zero,then C. 1= 0 and 2 = 0.2 4.if net contact force on block A is normal force,then D. 1= 0.4 and 2 = 0.8
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 13:36:00 IST
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since they have common acceleration they can be considered as a system now for the system of A&B mgsin37 - 2 mgcos37 = ma gsin37 - 2 gcos37 = a simplifying we get 6 - 8 2 = a ---------------------(1) now for block A mgsin37 + 1 mgcos37 - ma (pseudo force)= 0 gsin37 + 1 gcos37 = a simplifying we get a = 6 + 8 1 --------------------------(2) from 1 and 2 6+8 1 = 6 - 8 2 or 1 = - 2 therefore it is option B correct me if i"m wrong
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 15:22:23 IST
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i think 3 is A and C 1 mgs = 0 1 =0 case 2 2 mgs = 0 2 =0 therefore it is A and C
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 15:36:01 IST
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what i think is that since u have said a1 = a2 only when option B is correct hence a1 ! = a2 when option a,c,d are correct
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Impossible To be Impossible is Impossible |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 21:20:44 IST
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hey the answrs according to the solution given by Brilliant tutorials is: 1. A,B 2. C,D 3. A,B,D 4. A,C and my friend ganesha..u can consider it as a system only wen u can confirm that they move together..please justify... i am really very tensed about such kind of questions..pls somebody help........with proper solution..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 13:54:32 IST
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http://www.locuseducation.org/component/option,com_fireboard/Itemid,26/func,view/catid,10/id,524/#524
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 22:15:26 IST
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THE FIRST PART..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 22:16:32 IST
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SECOND AND THIRD PART..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 22:17:31 IST
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FOURTH PART..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 22:18:10 IST
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ok for the first one A is correect as there is no friction between the wedge and block B the whole A and B can be considered as one system with common acceleration
so from my present and previous post the answer for 1 is A) and B)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2008 22:20:14 IST
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since a1 is not equal to a2 the other two options must be true fior this therefore for 2 answer is C) , D)
[ thanks anchit]
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Apr 2008 14:34:27 IST
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http://www.locuseducation.org/component/option,com_fireboard/Itemid,26/func,view/catid,10/id,528/#528
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