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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 May 2007 17:32:00 IST
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sin +cos =?
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abhinava soundar |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 May 2007 17:35:14 IST
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sin + cos = 2 [sin / 2+ cos / 2] = 2sin( + /4]
This is the most common simplification ... though many more are possible
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 May 2007 17:50:55 IST
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hi abhinav........sinQ + cosQ can also b written as root(( sinQ + cosQ)^2)= root(1- sin2Q) or as elessar solved soo...plz do make it clear wot do u exactly wanna ask :) thanq
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 May 2007 21:34:13 IST
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Dear abhinavasoundar,
we are not getting what exactly you want to ask .
as elessar_iitkgp and ruhi has given you the two different forms in which you can transform the (sin +cos ). so please post the complete question.
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