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Blazing goIITian

Joined:	11 Feb 2007
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17 Aug 2007 23:25:16 IST

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GENIUS QUESTION

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The debroglie wavelength of a nuetron at 927 degree calcius is lambda. What will be it's wavelenth at 27 degree calcius????

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Karthik M

Blazing goIITian

Joined: 1 May 2007

Posts: 2830

18 Aug 2007 00:12:02 IST

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2 Lambda

CyBorG

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Joined: 6 Jan 2007

Posts: 706

19 Aug 2007 11:30:46 IST

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Karthik2007 has given the correct answer.
Here is the explanation,
de-Broglie wavelength at absolute temperature T is

=h/

(3mkT) Where k is Boltzmann constant.

At 927 degree celcius,

=h/

(3mk(1200))

At 27 degree celcius,

₁=h/

(3mk(300))

So

₁=2

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