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tarun_bits (639)

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can we aply kinematic equations in this case,,,,
as i think here..
t=kx2 ,so.. x=root of t/k..
and so we cant apply as this is non-uniform
am i right
 


<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>





    
budku007 (396)

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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>





Anyone who has never made a mistake has never tried anything new
You can never solve a problem on the level on which it was created.
When you are courting a nice girl an hour seems like a second. When you sit on a red-hot cinder a second seems like an hour. That's relativity

Purpose of solving a problem is not simply to get the answer(the answer is only an evidence) but to develop your thinking ability
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dinesh_ddt (163)

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not that the motion is non uniform
its acceleration is also changing wrt 2 time so we cant apply

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karthik2007 (3349)

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What do you want here? If you want the displacement, it will be the area under the curve. If you want the velocity at any instant, it will be the derivative of the function at that point

Will nip in at times to solve problems :)
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utkarshsingh_91 (39)

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no!!
differentiate both the sides wrt t
dx/dt=a
and
a comes out to be = 1/k2x
since a depends upon x so acceleration is not uniform and thus this motion cant be used with kinmatic eqs..





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