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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: gravitation
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[Post New]6 Apr 2008 10:33:35 IST
    Subject: gravitation
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Tanya_verma (5)

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Two particles each of mass m start to approach each other from a large separation due to mutual gravitational attraction. When separation becomes r, what is the magnitude of momentum of each particle in the frame of center of mass.
    
[Post New]6 Apr 2008 11:40:52 IST
    Subject: Re:gravitation
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karthik2007 (3375)

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m2G(2m)/r ?
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[Post New]6 Apr 2008 12:16:49 IST
    Subject: Re:gravitation
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Tanya_verma (5)

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no the answer given is   hw??
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[Post New]6 Apr 2008 12:24:09 IST
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Conjurer (568)

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Assuming there is no other body exerting force(s) on the bodies, then there is no net external force.Hence CoM remains at rest.

Now inital energy 0.

0 = mv^2 - Gm^2/r

root(Gm/r) = v

So momentum = mv = root(gm^3/r)
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