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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Apr 2008 10:53:10 IST
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The heavier block in an atwood machine has a mass twice that of the lighter one.The tension in the string is 16 N when the system is set into motion.Find the decrease in the potential energy during the first second after the sysem is realeased from rest?
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18 Apr 2008 17:06:07 IST
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18 Apr 2008 17:09:41 IST
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2MG-T=2MA
T-MG=MA
MG=3MA
A=G/3
T=2M(G-a)
16=2M(2G/3)
16=4MG/3
16*3/4=MG
12=MG
M=12/G
CONSIDER THE MOTION OF THE BIGGER BLOCK
S=1/2AT^2
=G/6
POTENTIOL ENERGY DECREASED=24/G*G/6*G=4G
CONSIDER THE MOTION OF THE SMALLER BLOCK
DISTANCE WILL BE SAME
POTENTIOL ENERGY INCREASED
=12/G*G/6*G=2G
THEREFORE POTENTIOL ENERGY DECREASED=2G=19.6
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