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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: H.C VERMA PROBLEM PAGE NO 80 PROB NO 23, PAGE NO 81 PROB 28
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BALGANESH (654)

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H.C VERMA PROBLEM  PAGE NO 80 PROB NO 23, PAGE NO 81 PROB 28
 
    
ramyani (2591)

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solved it. searching.

it is not important where u stand, but in which direction u are moving
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lokeshsardana (685)

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part 1 or 2

LOKESH SARDANA,
department of Production and Industrial engineering,
Indian Institute of Technology,Roorkee.


Happiness can be found, even in the darkest of times, if one only remembers to turn on the light.
Albus Dumbledore
Harry Potter and the Prisoner of Azkaban movie


There are only two ways to live your life. One is as though nothing is a miracle. The other is as though everything is a miracle.
-- Albert Einstein

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ramyani (2591)

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28,

FOr 28

T - 1*10 = A (1)
and Tension of the lower sytem is half of the first......Since the pulley is massless T" = T/2

20 -T/2 = 2A -2a .............(2)

30 - T/2 = 3A + 3a............ (3)
Three equations 3 variables solve these..............

u will get A = 10- 5a
Then plug it in other equation
u will get
A = 190/29 .........which is same as 19g/29 upwards
therefore for m1 and m2
17g/29 downwards
21g/29 downwards

Then use s = ut + 1/2 at square

where u is 0 s is 20/100 m solve u will get
20/100 =1/2*9.8* t^2
T=.2459
which can be aprooximated to .25 sec.......

p.s. I could not locate mine. I m pasting
vichu_487's solution.
Hope it wil help.


it is not important where u stand, but in which direction u are moving
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