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Mechanics

lokesh rawat's Avatar
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21 Sep 2007 21:22:00 IST
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A body starts bslipping down an incline and moves half meter in half seconds how long will it take to move the next half meter.


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Bipin Dubey's Avatar

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Joined: 23 Jan 2007
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21 Sep 2007 21:55:09 IST
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Use   s = ut + (1/2)at2 = (1/2)at2

At t1=1/2, s=1/2  :

1/2 = u(1/2) + (1/2)a(1/2)2

a = 4  (for u=0)

When s=1 :

1 = ut2 + (1/2)at22

t22 = 2/a = 2/4 = 1/2

t2 = 1/2

Hence time taken to move next 1/2 metre = t2 - t1 = 1/2 - 1/2  sec




Love Shah's Avatar

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Joined: 8 Jun 2007
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21 Sep 2007 23:02:30 IST
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let the mass of the body be m, and angle of inclination be theta.

ignoring friction,

mg.sin(theta) = m.a

a=g sin(the.)

1/2= 0 + 1/2 .gsin(theta) .(1/2)^2

= sin(theta) = 4/10

= a= 4

v ( after have second) = (2*4*1/2) ^ 1/2

v= 2

now

1/2 = 2t + 2t^2

t= 0.21 seconds

Ignore the negative value in quad. since time cant be -ve.

Plz. rate me!!!
Rohan Bhattacharjee's Avatar

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Joined: 5 Jun 2007
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21 Sep 2007 23:18:28 IST
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gr8 work



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