IIT JEE , AIEEE Forum - Physics , Mechanics

mukundeng12

A car weighs 1800kg. The distance b/w its front nd back axles is 1.8m

Its centre of gravity is 1.05m behind the front axle . Determine the force exerted by level ground on each front wheel nd each back wheel

cvramana

Let the force on each front wheel be P and that on each back wheel be Q

Therefore for linear equilibrium

2P + 2Q = W -------------- (1)

Where W = 1800 g newton ------------------ (2)

Also the distance between the axles is 1.8 m and that between the front axle and the C.G. is 1.05 m, the distance between the back axle and the C.G. will be 0.75m.

Therefore for rotational equilibrium about C.G. we have

2P x 1.05 = 2Q x 0.75 ------------------ (3)

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