Momentum = MV
Now momentum doubled means that "Velocity is doubled"
keeping into account that "mass remains constant"
Hence new V0 = 2V
K.E = (1/2)M(V0)2
K.E (new) = (1/2)M(2V)2 = 4 (1/2)MV2 = 4 (k.e)
Hence if momentum is doubled then KE becomes 4 times initial KE.
Hope it helps.
Momentum = MV
Now momentum doubled means that "Velocity is doubled"
keeping into account that "mass remains constant"
Hence new V0 = 2V
K.E = (1/2)M(V0)2
K.E (new) = (1/2)M(2V)2 = 4 (1/2)MV2 = 4 (k.e)
Hence if momentum is doubled then KE becomes 4 times initial KE.
Hope it helps.