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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Nov 2007 19:52:20 IST
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A Smooth semi-circular wire track of radius R is fixed in a
vertical plane.One end of a massless spring of natural length
(3R/4) is attached to the lower point of O of the wire track
A small ring of mass 'm',which can slide on the track , is
attached to the other end of the spring.The ring is held
stationary at P such that spring akes an angle 600 with the vertical.
The spring constant K = mg/R.
Consider the instant when the ring is released.
a)Determine the tangential acceleration of the ring and the
normal reaction.
The one who answers gets 2 salutes from me.
Challenge for all !!!!!!!!!!
(If answered then salutes but if no answer then I will give
the solution by tomorrow)
Cheers!!!!!!@@@!!!!!!!!!!!!!
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Always available for help !
But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.
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20 Nov 2007 20:23:59 IST
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Is nobody able to do this......!!!!!!!!!!!
Cmon where are the geniouses who were discussing Rotation
yesterday.??
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Always available for help !
But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.
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what's the answer ?? ??
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Who says nothing is impossible.
I've been doing nothing for years !!..............
I know KUNG FU KARATE
and 47 other dangerous words.............
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20 Nov 2007 20:29:55 IST
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Wait... just saw the sum... trying my shot at it... dont give the answer now
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Will nip in at times to solve problems :)
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20 Nov 2007 20:31:24 IST
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normal reaction is mg(8cos - 1 ) / 8
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20 Nov 2007 20:31:42 IST
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don't give the solution
but just tell the answer
u can also send it to my nudgebook if u don't want it to be here....
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Who says nothing is impossible.
I've been doing nothing for years !!..............
I know KUNG FU KARATE
and 47 other dangerous words.............
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20 Nov 2007 20:31:47 IST
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The answers are:
N=????
Tangential acceleration = ????
Try solving..............will post the solution by tomorrow.
Cheers!!!!!!!!!!!!!!!
As Karthik said not to answer.
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Always available for help !
But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.
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20 Nov 2007 20:35:23 IST
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Is the point P Touching the line passing thru C?
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Will nip in at times to solve problems :)
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20 Nov 2007 20:48:53 IST
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this question is useless yaar..aint it just too tuf ??
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iit-zone.blogspot.com
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20 Nov 2007 20:50:26 IST
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Will it be like,the initial tangential acc will be downwards, assuming that point P to be on the horizontal line from the center?
So m(aT) = mg + kx cos60 ?
plz correct me if i am wrong.
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20 Nov 2007 20:55:36 IST
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no nitish,,,,
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20 Nov 2007 20:57:30 IST
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hey, plz tell me if i am doing alrite.
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20 Nov 2007 20:59:30 IST
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Is alpha = g(8- 3/4 3)/R???
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Will nip in at times to solve problems :)
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20 Nov 2007 22:19:05 IST
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normal reaction = mg(1/2 - sqrt(3)/8)
tangential acceleration = g(sqrt(3)/2 + 1/8)
centripetal acceleration = g(1/2 - sqrt(3)/8)
am i rite????
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