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Blazing goIITian

Joined:	21 Mar 2012
Post:	1457

5 Apr 2012 22:23:32 IST

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509

IIt problem

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An horizontal rod has a bead which can slide along its length and initially placed at distance L from end A of the rod .....the rod is set in angular motion about A with constant angular acceleration `y` ,if the coe.of friction is `x` and gravity is neglected then the time after which the bead starts sliping is............

Comments (11)

kartikAIR1

Blazing goIITian

Joined: 2 Mar 2012

Posts: 304

5 Apr 2012 22:39:54 IST

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Sqrt [x/y]

Tarun Garg

Blazing goIITian

Joined: 21 Mar 2012

Posts: 1457

5 Apr 2012 22:43:59 IST

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KARTIKAIR1 will u pls tell me the method i am frustrated by doing this pls===pls====pls bro!!!!!!!

kartikAIR1

Blazing goIITian

Joined: 2 Mar 2012

Posts: 304

5 Apr 2012 23:00:45 IST

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force exerted by rod on bead is xmly equate it to centrifugal force mw^2l where w = yt . u get t...! o

Tarun Garg

Blazing goIITian

Joined: 21 Mar 2012

Posts: 1457

5 Apr 2012 23:05:36 IST

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ok thanks u r my GODFATHER on goiit okkkk

kartikAIR1

Blazing goIITian

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Posts: 304

5 Apr 2012 23:16:45 IST

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Kyu bhai, aaisa kya kar diya maine ??

Tarun Garg

Blazing goIITian

Joined: 21 Mar 2012

Posts: 1457

5 Apr 2012 23:18:24 IST

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yar u r superb in physics ad my weakest point is physics

Tarun Garg

Blazing goIITian

Joined: 21 Mar 2012

Posts: 1457

5 Apr 2012 23:22:17 IST

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kartik which institute do u studyyy

kartikAIR1

Blazing goIITian

Joined: 2 Mar 2012

Posts: 304

5 Apr 2012 23:50:39 IST

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resonance

Sana Irfan

Cool goIITian

Joined: 11 Feb 2012

Posts: 57

7 Apr 2012 15:29:18 IST

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how will we get w=yt? plz explain

M kartik

Cool goIITian

Joined: 29 Mar 2012

Posts: 62

7 Apr 2012 17:31:46 IST

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its a gr8 question...a lot more questions in dc pandey of the same concept..

M kartik

Cool goIITian

Joined: 29 Mar 2012

Posts: 62

7 Apr 2012 17:39:57 IST

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@ sana

therefore,

wo=o so...w=yt

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