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a bullet is fired from a gun.the force on the bullet is given by F=600-2*10^5t where F is in Newton and t is in sec. The force on the bullet becomes zero as soon as it leaves the barrel.what is the avg impulse imparted to the bullet
A) 8N s
B)0
C)0.9N s
D)1.8N s
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nageen
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Joined: 27 Dec 2011
Posts: 116
30 Dec 2011 22:38:33 IST
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wen F=0, 600-2*10^5t=010^5t=300t=(log3+2)/5impulse is integral Fdtintegral (600-2*10^5t)dt thev limits of integration are frm 0 to (log3+2)/5
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