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Cool goIITian

Joined: 13 Aug 2011
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29 Dec 2011 12:31:58 IST
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impulse
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 a bullet is fired from a gun.the force on the bullet is given by F=600-2*10^5t where F is in Newton and t is in sec. The force on the bullet becomes zero as soon as it leaves the barrel.what is the avg  impulse imparted to the bullet

A) 8N s

B)0

C)0.9N s

D)1.8N s


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Hot goIITian

Joined: 27 Dec 2011
Posts: 116
30 Dec 2011 22:38:33 IST
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wen F=0, 600-2*10^5t=010^5t=300t=(log3+2)/5impulse is integral Fdtintegral (600-2*10^5t)dt thev limits of integration are frm 0 to (log3+2)/5

Hot goIITian

Joined: 27 Dec 2011
Posts: 116
30 Dec 2011 22:41:00 IST
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wen F=0, 600-2*10^5t=0,10^5t=300,t=(log3+2)/5,impulse is integral Fdt...integral (600-2*10^5t)dt.. the limits of integration are frm 0 to (log3+2)/5
Viraat Gupta's Avatar

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Joined: 21 Jun 2011
Posts: 688
14 Feb 2012 12:53:51 IST
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in this question main part was to identify the limits , and you can do that as told above



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