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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jun 2007 19:44:29 IST
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Inicial acceleration of a particle moving in a straight line is a0 and inicial velocity is zero. The acceleration reduses continuesly to half in every t0 seconds as a = a0 / 2(t/t0). Find terminal velocity of the particle .
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jun 2007 20:52:00 IST
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what is the expression??/ well whatever it may be.....
write a = dv/dt & then integrate it..... u will surely get the answer...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 21:09:07 IST
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im not getting d ans. wat does terminal vel actually means? a = 1/2t (a, t, ) hope u got the expression...
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Keep working....................Iam comming..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 21:40:22 IST
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terminal velocity is the final velocity of the body, even when the acceleration is acting on it , at t = infinity.
here your acceleration is an exponential expression..
a = a0e-kt here k is equal to ln2/t0 now put a = dv/dt
integrate from limits a0 to a, and t = 0 to infinity.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Jun 2007 21:52:07 IST
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I am getting the answer probably it is a0.t0 / 2 Ans
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Jun 2007 00:01:12 IST
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Dear you wrote a = a0 / 2(t/t0) since the object is starting from rest so at t= 0 the acceleration becomes infinite which is not physically possible .
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Bhupesh.M |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Dec 2007 13:28:45 IST
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IT IS THE FINAL VELOCITY OF ANY MOVING BODY. USE FORMULA OF VELOCITY=DISTANCE/TIME.
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RUSHIKESH |
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