IIT JEE , AIEEE Forum - Physics , Mechanics

loveshah

a body takes time 't' to reach a maximum height when projected vertically downwards.

calculate the time reaquired for it to reach half the max. height.

answer should be in terms of t only.

explain the steps please.

nishant_88

how can a body reach max height when its projected downwards????I think there's some mistake in the question..........

partha

if i am correct the body must be projected downwards.
to reach maxm height,h
h = 1/2*a*t^2
t= [ (2*h)/g]^1/2

for half the maxm height
h/2 = 1/2*a*T^2

T=[ h/g]^1/2

T = t/ 2^1/2

krishna.gopal

Good answer partha. Just one mistake. To reach maximum height the body should be projected upwards

rajaieee

lets consider the body to be thrown vertically upwards-

(A body cant attain maximum height on throwing vertically downwards)

Let maximum height be h,

s=h/2,u=0

s=ut+1/2gt^2

h/2=1/2*10*t^2

t^2=h/2*2*1/10

=h/10

.

. . t=h/10^1\2

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