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15 Jan 2007 20:05:14 IST

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Kinematics

Engineering Entrance , Medical Entrance , AIPMT , JEE Main , AIIMS , JEE Advanced , Physics , Mechanics

^{the displacement of a particle is given by the eqution}

S = 3t^3_5t²+4t-7

Then Calculate the displacement and distance in the first 5 seconds.

Comments (4)

CyBorG

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15 Jan 2007 20:11:41 IST

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Substitute t=5 to get displacement and distance ie 527

ajay9852

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15 Jan 2007 20:54:35 IST

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no friend that is the displacement but 4 distance its different.since the acceleration is time varying.........

edison

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15 Jan 2007 21:13:50 IST

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Displacement and distance of a particle will be same provided the particle is having a rectilinear motion or it is moving in a straight line.

Thus the displacement and distance will be same only assuming that particle is moving in a straingt line, and is obtained by putting t = 5 in the expression of S.

Acceleration ofcourse is not constant in this case.

ajay9852

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16 Jan 2007 08:20:58 IST

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sir

the since the acceleration is not constant, the direction of motion may change.....

and we can use the equatons of motion only for uniformly accelerated motion......

this will affect the distance travelled though we can find the displacement by direct substitution........

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