IIT JEE , AIEEE Forum - Physics , Mechanics

karthiksrichandra

The height tap is 5 mts. when the fifth drop was going to fall first drop fall.What is the distance between third drop and flour.

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apurviitjee2008

is the answer 0.9 mtrs

apurviitjee2008

is the answer 4.8 mtrs ?

snandkeolyar

Is it 0.8m,if g=10?

seifo_90

Is it 0.2

Nithy

I think it is 1.4m.

5=1/2 gt^2

t=1

drops fall at regular intreval.

intreval=1/5= .2

s=1/2 gt^2

s4=1/2 *10*.6^2

s3=1/2*10*.8^2

subtracting,

ans: 1.4m

kghedriu

time taken for the first drop to fall= [2h/g]^1/2 = 1 sec

since drops fall uniformly, 5 drops fall in 1 sec...

hence 1 drop falls in 1/5 = 0.2 sec

so, third drop falls wen t= 0.4

.: the third drop shud have fallen for 1-0.4= 0.6 sec

dist covered by 3rd drop= 1/2*g*0.6*0.6

= 1.8 m

.: distance of the third drop from the floor= 5-1.8 = 3.2 m

hope u got it...

thank ya..

Goutham Harsha .K {i find bliss in ignorance ^_^ }

edison

Well done kghedriu

elessar_iitkgp

Good solution kghedriu

karthiksrichandran

it is 3.75mt