| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jul 2007 13:41:19 IST
|
|
|
a stone is thrown with some velocity upward the ground after moving 98m its velocity becomes zero.then what is the initial velocity applied to the stone.
|
|
|
|
19 Jul 2007 14:51:54 IST
|
|
|
s = 98m/s.
a = -9.8m/s2
v=0.
u=?
v2-u2=-2gh.
u2=2x98x9.8
u=43m/s.
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
19 Jul 2007 16:17:35 IST
|
|
|
Either use the above method (as suggested by karthik)
or
Simply use law of conservation of energy
energy at top = energy at bottom
mgh = 1/2 m v^2
gh = 1/2 v^2
v = root of 2gh
v = 43. something
either ways u r getting the exact same answer........
Rate If Useful
|
Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
this reply: 2 points
(with 0
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
19 Jul 2007 19:36:45 IST
|
|
|
yup the conventional method is the one given by karthik , and since there is no non conservative present the method given by nunoxic will give the right result too.
Well Done both of you
|
There is no better feeling in this world than being a winner! |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
21 Jul 2007 21:52:42 IST
|
|
|
h = u2 /2g u2 = 2 g h solving u =  2* 9.8*98 solving this gives 43.82 m/s
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
21 Jul 2007 21:54:22 IST
|
|
|
h = u2 /2g u2 = 2 g h solving u = 2* 9.8*98 solving this gives 43.82 m/s
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
