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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 13:28:35 IST
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can a projectile have a semicircular trajectory?? If so at what angle of projection??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 14:20:15 IST
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If you want to have exact semicircle as the trajectory thn it shud b project at an angle of 90 with the horizontal or say vertically upwards, but u need to hav an acceleration in the horizontal direction which could push it laterally. this accl can b created by winds......
If you want the trajectory to b a part of the circle(but u need to hav an acceleration in the horizontal direction), thn its easy....take a chord of the circle as the range and max hight attained. this is easy i think u can solve from the hint
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Truly Mittal
B.Tech IIT Guwahati
trulymittal@gmail.com |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 15:32:09 IST
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Hi Consider the case of throwing a rojectile from a tower on the earth.If its velocity is less say less than 8km/s then it will fall directly on the earth. If its velocity is equal to 8km /s then it will follow a circular path. If its greater than that it follows elliptical path. So if you write the equation of the trajectory of projectile, It comes to be a parabola. So for any angle it cant be a semi-circular one. Pls tell if i am wrong. Cheers!
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Act..dont just think!!! It saves u time.... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 15:40:52 IST
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Hi Kiran.Long time after meeting you.You even bunked on our last working day.
I think truly is right.When it is projected vertically and if it has horizontal acceleration equal to g then it will be a circular path.
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ADARSH
NITK Surathkal
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 15:55:22 IST
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Hi adarsh I couldnt come as i was bit busy( completin and submission of records) . The question is can a projectile have a semicircular trajectory? While considering the trajectories we never take into consideration external forces such as air resistance , or the effects of wind . So in that case getting a semi-circular track is not possible. If external force is considered then its possible as you have said. Then Hows your preparation??? Cheers!
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Act..dont just think!!! It saves u time.... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 16:24:29 IST
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It is possible iff external forces are considered.
Preparations are going on rather fast.But so little time so much to do.
Hows ur preparation and how was the lab exam?
Cheers!!!
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ADARSH
NITK Surathkal
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2007 21:14:58 IST
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for having a semicircular trajectory the pt. as center of semi-circle will lie at center of the horizontal range which will be the diameter as radius is same in the semi circle
equate the eqn of max. ht. and equn of range/2
this should give the answer
arctan 2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 20:12:21 IST
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No a projectile can not have a semicircular trajectory
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 23:21:24 IST
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Hi, Edison sir, Why can't the prjectile have a semi-circular trajectory. If it has then rahge is twice the max height attained. And angle of projection comes out to be Tan-12. Please tell if i am wrong.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 23:55:20 IST
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Check my msg in http://www.goiit.com/posts/list/4495.htm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2007 00:13:41 IST
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Ya If the half of the range is equal to the maxmheight the its trajectory will be a semi-circle. 1/2(R) =H or, (u2sin2x)2g = u2sin2x/2g sin2x= sin 2x  2 cosx = sinx tanx= 2 x= tan -1(2)  ANS Don't forget to give a solute.
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