IIT JEE , AIEEE Forum - Physics , Mechanics

sonalisapal

it is possible to project a particle with a given velocity in 2possible ways so as to make it pass through a point P at a distant from the point of projection.the product of the times taken to reach this point in the 2possible ways is then proportional to??? answer given is r(range)

kirtana

hi

suppose the body is projected at an angle @with speed u..

then

range = (u)sqr sin2@ /g

therefore sin 2@= rg/(u) sqr

ther is another value sin $ for which

sin $=rg/(u) sqr

therefore sin2@ = sin$

therfore either 2@=$

or 2@ = 180 - $

i.e @1 = $ / 2

and @2 = 90 - $/2

now take the 2 values of the angle of projection and find the values of time

take the product and use trigo formula to solve. u'll get the answer as a constant into range

im very sorry but finding it very difficult to type the angles and solving

snigdha

Hi Kirtana

when u type a ques. or reply to a ques., there is a toolbar just above it where the first box has symbols like

,

BAC,

,

etc...

I believe this would definiltely help u out..

puneet

Good work!!

gomurali

Range will be same for the angles of projections

and 90-

. t₁* t₂ = 2u sin

/g *2u sin (90 -

)/g = 2 . 2 u² sin

cos

/g = 2 R there fore the answer is

to R.

Ask & Discuss Questions with Community & Experts