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a thief in a stolen car crashes through a police checkpost at his top speed of 90 km/h...a mototrcycle cop reactng aftr 2 sec acclerates frm rest at 5 m/sec^2..his top speed being 108km/hr..find the maxm seperation between police nd thuief....












After 2 sec., dist travelled by theif = 2 x 25 = 50 m (90km/h = 25m/s)
Taking this instant (when cop starts chasing) as t = 0, at any instant t, the dist of theif from checkpost = 25t + 50
Dist. of cop from checkpost = 1/2 at2 = 5/2 t2
Let x be the separation b/w them which is given as function of time as x = (25t + 50) - 5/2 t2
When separation is max. dx / dt = 0
i.e. 25 - 5t = 0 ==> t=5
Therefore, x = 175 - 62.5 = 112.5 m