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Community Discussion Question:
Kinetic Energy
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Mechanics
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30 Nov 2007 13:52:19 IST
Subject:
Kinetic Energy
tinchubenz
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When the K.E. of a body is increased by
300%
, the
momentum
of the body is increased by:
a.20%
b.50%
c.100%
d.200%
30 Nov 2007 14:05:38 IST
Subject:
Kinetic Energy
harsha_27
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200% because momentum (MV)=sqr.rt.[2m(k.e.)]...
"Nenenthedhavano naake teleedu"
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30 Nov 2007 14:46:15 IST
Subject:
Kinetic Energy
rooney
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Nope. Its 100%.
Velocity is doubled. So, momentum is doubled. So, increase is of 100%.
http://14-69-8.blogspot.com
My blog
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30 Nov 2007 16:00:17 IST
Subject:
Kinetic Energy
spideyunlimited
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KE = 1/2 m v^2
KE is increased by 300% means that new KE = 4 x original KE
[ original KE + (300 / 100) * original KE ]
so new KE = 4 * 1/2 * m * v^2
= 1/2 * m * (2v)^2
so velocity has doubled.
so if original momentum was mv
new momentum is m(2v)
= twice of original momentum
means momentum has increased by 100% [ mv + (100/100)mv ]
---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited
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30 Nov 2007 22:15:55 IST
Subject:
Re:Kinetic Energy
karthik2007
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The basis for such problems is simply this:
Kinetic Energy = (Momentum)
2
/2 x mass
Will nip in at times to solve problems :)
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