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Mechanics

Cool goIITian

Joined:	9 Sep 2007
Post:	36

23 Sep 2007 10:34:26 IST

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458

Laws of Motion

None

A force of F(vector)=8i-6j-10k Newton produces an acceleration of 1.41m/s² on a body.Find the mass of the body.

Give the steps of the calculations

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SAVVEJ

Blazing goIITian

Joined: 4 May 2007

Posts: 697

23 Sep 2007 11:12:05 IST

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magnitude of force = root of 8² +6² +10²
=root of 200
=10root2

force =mass * acceleration
10root 2 = mass * 1.41
10 * 1.41 =mass* 1.41
.: mass = 10 kg

SHUBHAM AGRAWAL

New kid on the Block

Joined: 15 Sep 2007

Posts: 4

23 Sep 2007 16:58:01 IST

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GIVEN- F=8I -6J-10K
A=1.41M/S2
F= MA
THEREFORE M=F/A
MAGNITUDE OF F=(64+36+100)ROOT =200ROOT=10*2ROOT
M=10*2ROOT/1.41=10*1.41/1.41
=10
HENCE MASS=10KG

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