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7 Nov 2008 19:14:52 IST

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448

laws of motion

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1)A monkey of mass 20kg is holdingt a vertical rope ,which breaks under a weight of 25kg.The max accln with which the monkey can climb up the rope is(g=10m/s^)

2)Frictional force b/w 2 surfaces is max for

1)sliding fr

2)rolling fr

3)static fr

4)limiting fr

Comments (6)

chetanbathija

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7 Nov 2008 19:28:30 IST

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pls reply fst guys

Bharat Puri

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7 Nov 2008 19:30:54 IST

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1. Is the answer 2.5m/ss

2. Is the answer D.

Gaurav |spideyunlimited| Ragtah

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7 Nov 2008 19:36:38 IST

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1) 25g = m (g+a)
250 = 20 (10 + a)
a = 2.5 m/s^2

2) limiting friction is maximum

chetanbathija

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7 Nov 2008 19:42:21 IST

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can u pls give reason for my 2 Q?

Bharat Puri

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7 Nov 2008 19:47:27 IST

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Limiting friction is that friction if you exceed it then it converts to kinetic friction and body starts moving.So it is maximum.

Gaurav |spideyunlimited| Ragtah

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7 Nov 2008 19:58:05 IST

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max value of static friction is limiting friction and just beyond that, motion starts, and kinetic friction is less than it. Experimentally observed.

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