Home » Ask & Discuss » Physics. » Mechanics « Back to Discussion

Mechanics

Cool goIITian

Joined:	8 Jun 2007
Post:	42

22 Sep 2007 20:22:01 IST

0 People liked this

418

Laws of Motion(Challenging Problem)

None

Find accelration of the wedge ; given all surfaces are frictionless ..

PS .. angle 1 is

and angle 2 is

Share this article on:

Comments (2)

thevyzz

Blazing goIITian

Joined: 5 May 2007

Posts: 686

22 Sep 2007 20:41:13 IST

Like 0 people liked this

| g( m1cosAsinA - m2sinBcosB)/M |

Priyesh

Blazing goIITian

Joined: 18 Feb 2007

Posts: 1042

22 Sep 2007 21:02:20 IST

Like 2 people liked this

The ans is (1 / 2M) * g * (m₂sin(2) - m₁sin(2) )

see analyse the forces on the wedge

it's clear that the acceleration will be horizontal

the two blocks exert forces of normal reaction on the wedge = m1gcos

& m2gcos

now taking horizontal componets of both

m₁gcos

sin

& m₂gcos

sin

since they are in opposite direction we subtract one from the other

note: u don't have to bother about which one is greater so no need to put any mod sign)

therefore net horizontal force = Ma

=> m₂gcos

sin

- m₁gcos

sin

= Ma

=> a = (1 / 2M) * g * (m₂sin(2

) - m₁sin(2

) )

Quick Reply

Reply

	Some HTML allowed.
	Keep your comments above the belt or risk having them deleted.
	Signup for a avatar to have your pictures show up by your comment
	If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team

Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor

@ INR 1,995/-

For Quick Info

Find Posts by Topics

Physics.

Topics

9395

20091

3672

2186

7617

2827

2638

Mathematics.

Chemistry.

Biology

Institutes

Parents

Board

Fun Zone