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Mechanics

Scorching goIITian

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19 Feb 2009 21:04:57 IST

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348

Laws of Motion question

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Jabroo !!

Blazing goIITian

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20 Feb 2009 07:15:23 IST

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is the answer D none of the above..pls verify and tell me...

XYZ

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20 Feb 2009 08:20:22 IST

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I think the answer is (C). If it is correct, then I'll give you the solution (if required).

Bhaskar Tetarbe

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20 Feb 2009 12:32:21 IST

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No Ashish its not (C). But how did you conclude this ?

Mr.Scorpions

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20 Feb 2009 13:57:04 IST

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The answer is coming as (D) it doesnot match with any of the given options................... i am getting 10/3 as initial acc but final not 4 as given in the option...............i am getting 6 instead!!

Bhaskar Tetarbe

Scorching goIITian

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20 Feb 2009 20:30:52 IST

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Mr.Scorpions the correct answer given is B. I have no idea how it could be this.

AViK

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21 Feb 2009 00:23:59 IST

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This is when the blocks just start moving.....

V hav..... 2g = T+ 2a

=>2g = (6a) + 2a => a= 2g/8 =20/8 m/s²

This will b the initial acc. of the blocks....

CASE 2)When the full string is pulled dwn

The equation bcomes...

=>T' + 2a' = 2g + g

=>6a' + 2a' = 3g

=> a' =3g/8 = 30/8 m/s²

That is the final acceleration...

So option (b) shud b correct....

Hope u understand.....Rates welcome....

ABINASH

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21 Feb 2009 13:15:54 IST

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in da 1st case.... the cord n the trolley can b considered together as a system n the tension @ the rite end f the cord pulls the system....so, we get: T = 6a and 2g - T = 2a or a = 2g/82nd case, we hve the trolley @ the pulley.... and the load and cord can be considered as a system...so, we get, T= 5a1 and 3g - T = 3a1 or a1= 3g/8.Jst we need to see dat tensions on both sides of da cord r unequal... dat wud do it....cheers

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