|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Dec 2006 19:01:06 IST
|
|
|
Sir, my question is A bullet of mass 20g moving horizontaly at a speed of 300m/s is fired into a wooden block of mass 500g suspended by a long string. The bullet crosses the block and emerges on the other side. If the centre of mass of the block rises through a height of 20cm,find the speed of the bullet when it emergesfrom the block?
|
|
|
|
18 Dec 2006 19:08:53 IST
|
|
|
Apply law of conservation of momentum to find the velocity of the bullet when it emerges out. Now the kinetic energy of block will be such that it acquires potential energy so that the center of mass of the block raises by 20cm Use (1/2)mv2 = mgh, find v for the block. substitute in the equation for conservation of momentum and get the required result.
|
The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
