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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 19:35:13 IST
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a man standing on the ground has to hold his umbrella at 30 with the vertical to keep the rain away . he throws the umbrella and starts running at 10kmph . he finds that the rain drops r hitting his head vertically . find the speed of the man wrt road and the moving man
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SHREYA |
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21 Mar 2008 20:36:58 IST
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the qsn should be find the speed of the rain wrt the man and the ground.
velocity wrt ground: 10 i - 10 3 j kmph
i.e speed = 20 kmph
speed wrt man 10 3.
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21 Mar 2008 20:46:18 IST
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could you edit your question do you want to find the actual velocity of the man??? or as hash includee said the velocity of rain wrt to man???
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22 Mar 2008 00:27:27 IST
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Let v1=velocity of the man with respect to the road,
v2= velocity of the rain with respect to the man
V= velocity of the rain with respect to the road.
So we have, V= v1+v2
To find the velocity with respect to the road,
we have,
Vsin30= v1
V= 10km/hr x cosec30= 20 km/hr
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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22 Mar 2008 00:30:59 IST
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For the second one,
We have,
Vcos30 = v2
v2= 20 x 3/2
v2= 10 3km/hr.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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22 Mar 2008 19:17:46 IST
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ya, instead of man it is rain, sorry
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SHREYA |
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22 Mar 2008 19:20:50 IST
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dear mujtaba4iit, can u please clear my doubt with ur last step in ur first post
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SHREYA |
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23 Mar 2008 00:16:03 IST
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I think u mean this: ''V= 10km/hr x cosec30= 20 km/hr''
If Vsin30= 10km/hr then
V/2= 10km/hr ........................... since sin30= 1/2
so V= 20km/hr
In that post i took sin30 on the other side to make it cosec30.
But anyway........ i think its clear now.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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29 Mar 2008 13:54:33 IST
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ya, 10q so much
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SHREYA |
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