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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Mar 2007 14:34:59 IST
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A solid sphere is set into rotation on a rough surface with linear speed v0 in forward direction and angular speed of (v/r) in anticlockwise direction .Find linear speed of sphere when it stops rotating .
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11 Mar 2007 14:37:10 IST
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hey manmadha, m extremely srry, but i have left rotation completely, so wont be able to contrivute anything to this question.... better u remove my name in topic..... and wait for shakir, he'll do it..... jst drop a nudge in his nudgebook!!!!!!!! once again srry
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Manasi....
NIT-Allahabad...
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The World out thr is waiting for U !!
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11 Mar 2007 14:41:18 IST
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Hi Manmadha, As sphere is rotating in anti clockwise direction it should slip . Torque due to friction at point of contact is 0 ,hence conserve angular momentum about point of contact of sphere and ground . Angular velocity of sphere is 0 at the time when rotation of sphere is stopped. -I w + m vo r = m v r I = (2/5)mr^2 v = (3/5)vo. 
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11 Mar 2007 14:45:16 IST
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hi friend the ans is Vo-V this will be the velocity of centre of mass bye
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11 Mar 2007 14:46:41 IST
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hey aman ur wrong,vineet is right .Thanks vineet
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
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11 Mar 2007 14:52:13 IST
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sorry the ans is -Iw+MVoR=Mv'R you can eazily find the value of v' bye plzzz rate me
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