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 Community Discussion Question:
maths
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jul 2007 12:06:29 IST
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Integration of x^x dx
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tamal das |
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19 Jul 2007 15:59:12 IST
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put x^x=t
x.logx = log t
now differentiate
and proceed u will get the answer
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20 Jul 2007 12:31:32 IST
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x^x=t
xlogx=logt
diff. both sides wrt to x
and using product rule in lhs
x.1/x +logx= 1/t dt/dx
subst. t
we have
d x^x/dt= x^x(1+logx)
rhs is the ans....
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IIT- Imposible Is This(atleast fr meeeeeeeee) |
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