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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 20:57:03 IST
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Find the value of : [i=0 ] [1/0 ] [j=0 ] [1/0 ] [k=0 ] [1/0 ] 1/(3 i.3 j.3 k) [ i  j  k]
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2007 08:47:32 IST
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well the ans is 27/8.That is how it goes for solving first summation we goes from k=0 to infinity by that time 3i &3j remain constant so we can take them out as constant [i=0 ] [ ] [j=0 ] [ ]1/3i.3j ( [k=0 ] [ ]1/3k ) [i=0 ] [ ] [j=0 ] [ ]1/3i.3j (3/2) Simmilarily we get 3/2 from all three
so ans is (3/2)3 =27/8
also 1/0 is not  are u giving me a salute?
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adversities cause some men to break other to break records............i m of the other type....... :-) |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2007 16:32:26 IST
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well ankur has produced a fabulous..he deserves a salute..
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a 2nd year IIT DELHI student, doing B.Tech in chemical engineering |
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