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chinmay_saxena01 (565)

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hey guys i m not getting the answer....plz help me''''


a man in a balloon rising vertically with an accleration of 4.9m/s^2 releases a ball 2 sec after the balloon is let go from the ground.The greatest height above the ground reached ny ball is ?????


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learner (325)

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S= 0.5 at2


 =0.5*4.9*4


=9.8 m..


Is that right?


 

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rohitkuruvila (287)

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is it 14.7 m

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spideyunlimited (3493)

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s = 1/2 at^2
s = 1/2 * 4.9* 4
= 9.8 m

v = 0 + at
v = 4.9 * 2 = 9.8 m/s

V^2 - U^2 = 2as
0 - (9.8)^2 = 2*-9.8*s
s = 4.9 m

so Total height reached = 9.8 + 4.9 = 14.7 m

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learner (325)

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Sorry!!!Forgot all about inertia!!:-D

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