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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Sep 2007 14:49:54 IST
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moment of inertia of a thin circular disc is0.5 kgm2 the torqe req. to produce in the disc an angular accleration of 1 rad s-2 is?
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21 Sep 2007 14:55:00 IST
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wats d prob.??? simply apply formulae:-  = I .  = 0.5 X 1 N.m = 0.5 N.m
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21 Sep 2007 18:27:45 IST
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simple,
torque=M.I. * Angular acceleration
=0.5*1
=1 N.m
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21 Sep 2007 18:44:49 IST
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answer is:
torque = Moment of inertia * angular accleration
I = 0.5
acc = 1
=> torque = 0.5 * 1 = 0.5 Nm
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